COMPLEX NUMBER REPRESENTATION
An imaginary (complex) number z z z can be written as:
z = x + y i z = [ ∣ z ∣ ↑ modulus , arg ( z ) ↑ argument ] \begin{aligned}
z &= x + yi \\
z &= [ \;\; \underset{\begin{subarray}{c} \uparrow \\ \text{modulus} \end{subarray}}{|z|} , \quad \underset{\begin{subarray}{c} \uparrow \\ \text{argument} \end{subarray}}{\text{arg}(z)} \;\; ]
\end{aligned} z z = x + y i = [ ↑ modulus ∣ z ∣ , ↑ argument arg ( z ) ]
Other forms
z = x + i y z = x + iy z = x + i y can be rewritten as:
z = ∣ z ∣ cos ( θ ) + i ∣ z ∣ sin ( θ ) z = ∣ z ∣ ( cos ( θ ) + i sin ( θ ) ) ∴ z = ∣ z ∣ cis ( θ ) where cis ( θ ) = cos ( θ ) + i sin ( θ ) \begin{aligned}
z &= |z|\cos(\theta) + i|z|\sin(\theta) \\
z &= |z|(\cos(\theta) + i\sin(\theta)) \\
\therefore z &= |z|\operatorname{cis}(\theta) && \text{where } \operatorname{cis}(\theta) = \cos(\theta) + i\sin(\theta)
\end{aligned} z z ∴ z = ∣ z ∣ cos ( θ ) + i ∣ z ∣ sin ( θ ) = ∣ z ∣ ( cos ( θ ) + i sin ( θ )) = ∣ z ∣ cis ( θ ) where cis ( θ ) = cos ( θ ) + i sin ( θ )
Degrees and Radians
To switch between degrees and radians, use these constants:
1 ∘ = π 180 1 rad = 180 π \boxed{1^\circ = \frac{\pi}{180}} \quad \boxed{1 \text{ rad} = \frac{180}{\pi}} 1 ∘ = 180 π 1 rad = π 180
Degrees Radians 360 ∘ 360^\circ 36 0 ∘ 2 π 2\pi 2 π 270 ∘ 270^\circ 27 0 ∘ 3 2 π \frac{3}{2}\pi 2 3 π 180 ∘ 180^\circ 18 0 ∘ π \pi π 135 ∘ 135^\circ 13 5 ∘ 3 4 π \frac{3}{4}\pi 4 3 π 90 ∘ 90^\circ 9 0 ∘ 1 2 π \frac{1}{2}\pi 2 1 π 60 ∘ 60^\circ 6 0 ∘ 1 3 π \frac{1}{3}\pi 3 1 π 45 ∘ 45^\circ 4 5 ∘ 1 4 π \frac{1}{4}\pi 4 1 π 30 ∘ 30^\circ 3 0 ∘ 1 6 π \frac{1}{6}\pi 6 1 π
Finding the Modulus and Argument
Finding the modulus of a complex number is very simple, we just use Pythagoreas' Theorem.
z = x + y i ∣ z ∣ = x 2 + y 2 \begin{aligned}
z &= x + yi \\
|z| &= \sqrt{x^2+y^2}
\end{aligned} z ∣ z ∣ = x + y i = x 2 + y 2
The argument of a complex number z = x + i y z = x + iy z = x + i y is the angle θ \theta θ made with the positive real axis (cis ( θ ) \text{cis}(\theta) cis ( θ ) ). Because tan ( θ ) = y x \tan(\theta) = \frac{y}{x} tan ( θ ) = x y , we use the signs of x x x and y y y to determine the correct quadrant.
First, find the reference angle: α = tan − 1 ∣ y x ∣ \alpha = \tan^{-1} \left| \frac{y}{x} \right| α = tan − 1 x y .
Quadrant Location Signs Calculation Range of θ \theta θ I Upper Right x > 0 , y > 0 x > 0, y > 0 x > 0 , y > 0 θ = α \theta = \alpha θ = α 0 < θ < π 2 0 < \theta < \frac{\pi}{2} 0 < θ < 2 π II Upper Left x < 0 , y > 0 x < 0, y > 0 x < 0 , y > 0 θ = π − α \theta = \pi - \alpha θ = π − α π 2 < θ < π \frac{\pi}{2} < \theta < \pi 2 π < θ < π III Lower Left x < 0 , y < 0 x < 0, y < 0 x < 0 , y < 0 θ = − ( π − α ) \theta = -(\pi - \alpha) θ = − ( π − α ) − π < θ < − π 2 -\pi < \theta < -\frac{\pi}{2} − π < θ < − 2 π IV Lower Right x > 0 , y < 0 x > 0, y < 0 x > 0 , y < 0 θ = − α \theta = -\alpha θ = − α − π 2 < θ < 0 -\frac{\pi}{2} < \theta < 0 − 2 π < θ < 0